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【求助】英译汉 关于有关物质的 ?

  • xiaoyaogxzz
    2021/10/11
  • 私聊

专业英语

  • If any peaks are present in the chromatogram obtained with the Sample solution that have the same retention times as the peaks due to ethyl benzene and dicyclohexyl, subtract the areas of any such peaks from the peak areas at these retention times in the chromatograms of Reference solution A or Reference solution B (corrected peak areas of ethylbenzene and dicyclohexyl). Any such peaks in the Sample solution should be included in the assessments for the total ofother peaks.

    In the chromatogram obtained with the Sample solution , the area of any peak corresponding to benzaldehyde is NMT the difference between the area of the peak due to benzaldehyde in the chromatogram obtained with Reference solution A (0.15%) and the area of the peak due to benzaldehyde in the chromatogram obtained with the Sample solution

    In the chromatogram obtained with the Sample solution, the area of any peak corresponding to cyclohexylmethanol is NMT the difference between the area of the peak due to cyclohexylmethanol in the chromatogram obtained with Reference solution A(0.10%) and the area of the peak due to cyclohexylmethanol in the chromatogram obtained with the
    Sample solution

    In the chromatogram obtained with the Sample solution, the sum of the areas of any peak with a relative retention time less than that of benzyl alcohol and apart from the peaks due to benzaldehyde and cyclohexylmethanol is NMT four times the area of ethylbenzene in Reference solution A , corrected if necessary as described above (0.04%).

    In the chromatogram obtained with the Sample solution, the sum of the areas of any peak with a relative retention time greater thanthat of benzyl alcohol is NMT the area of dicyclohexyl in Reference solution A , corrected if necessary as described above (0.3%).

    Disregard any peak with an area less than 0.01 times that of the peak due to ethylbenzene in the chromatogram of Referencesolution A , corrected if necessary as described above.
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  • dahua1981

    第1楼2021/10/11

    应助达人

    如果样品溶液由于乙苯和二环己基而得到的色谱图中存在与峰保留时间相同的任何峰,则从对照品溶液A或对照品溶液B (乙苯和二环己基校正峰面积)色谱图中这些保留时间的峰面积中减去任何这类峰的面积。样品溶液中的任何此类峰都应纳入其他峰总数的评估。
    在样品溶液得到的色谱图中,苯甲醛对应的任何峰面积为NMT,对照品溶液A得到的色谱图中苯甲醛峰面积( 0.15 % )与样品溶液得到的色谱图中苯甲醛峰面积之差为NMT
    在用样品溶液得到的色谱图中,环己基甲醇对应的任何一个峰的面积为NMT由于环己基甲醇引起的峰面积之差

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  • xiaoyaogxzz

    第2楼2021/10/11

    我自己翻译的:大家帮我看看呢

    如果样品溶液得到的色谱图中存在与乙苯和二环己基峰保留时间相同的峰,从对照溶液A或对照溶液B(乙苯和二环己基的校正峰面积)色谱图中这些保留时间的峰面积中减去相应峰的面积。样本溶液中的任何此类峰都应包括在其他峰总数的评估中。
    供试品溶液色谱图中,苯甲醛的峰面积应不大于对照溶液A (0.15%) 色谱图中苯甲醛峰面积与供试品溶液中苯甲醛峰面积的差值。
    供试品溶液色谱图中,环己基甲醇的峰面积应不大于对照溶液A (0.10%) 色谱图中环己基甲醇峰面积与供试品溶液中环己基甲醇峰面积的差值。
    供试品溶液色谱图中,除苯甲醛和环己基甲醇峰外,相对保留时间小于苯甲醇的所有峰的面积之和不大于对照溶液A中乙苯面积的4倍,如有必要按上述方法进行校正(0.04%)。
    供试品溶液色谱图中,相对保留时间大于苯甲醇的所有峰的面积之和不大于对照溶液A中二环己基的面积,如有必要按上述方法进行校正(0.3%)。
    忽略任何面积小于对照溶液A色谱中乙苯峰的0.01倍的峰,如有必要按上述方法进行校正。

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