依风1986
第33楼2012/11/16
我们的17种元素工作曲线就是严格执行MATTEL的GLOP7409G版本对各元素的要求,Mn标液点是0.1mg/l.1mg/l,5mg/l,QC是2.0mg/l, 0.1mg/l对应强度是22137.2intensty,1mg/l对应强度是213618.4intensty,5mg/l对应强度是1047558intensty.就选择今天走曲线,个点实际浓度与理论偏差很小比如0.1,仪器走出来是0.103469 ,1仪器走出来1.00283 ,5,仪器走出是4.91976,QC理论是2,实际走出来基本在2.0几
砂锅粥
第35楼2012/11/16
请问标液是什么基体?
依风1986
第41楼2012/11/16
Requirements
一般测试要求
Composite testing, when permitted, must meet the following criteria:
复合测试,当允许时必须符合下列标准:
• Only permitted for total digestion method, not permitted for Soluble 1 and Soluble 2 method.
仅允许总量消解方法,不允许可溶性方法1和可溶性方法2。
• No more than 3 samples may be combined.
不得超过三种样品混合。
• The difference of 3 sample weights should be less than 0.02g. Determine which sample is
present in the smallest amount (weight) in the composite. For example: x is less than y and x
is less than z.
三个不同的样品重量不得超过0.02g。每个样品在混合试样中的含量要小于其它任意一个数量。
例如:x小于y并且x要小于z。
• Designate and record the measured concentration of heavy element in the composite sample
as”Cavg”
用”Cavg”代表和报告混合物中每种邻苯二甲酸酯的测量含量。
• Determine the maximum possible concentration of heavy element (Cmax) in a single sample as
follows:
Cmax=Cavg*(x+y+z)/x
按照下列公式确定单个样品中每种邻苯二甲酸酯最大可能含量:
Cmax=Cavg*(x + y + z)/x
• Compare the Cmax to the requirement limit. IF Cmax is less than limit, then each sample in the
composite sample is deemed comply with the requirement and no further testing is required.
If Cmax is greater than the limit. All samples in the composite sample must be tested
individually. When use the results from the total digestion test to satisfy soluble 1 and
Soluble 2 requirements, IF Cmax is larger than the soluble limits, soluble method 1 and 2 must
be performed.
用Cmax与要求的限值比较。如果Cmax小于限值,混合样品中的每个样品都符合要求,不必进一步
测试。如果Cmax大于限值。混合样品中的所有样品要分开测试。当用总量消解测试出具结果时必须
符合可溶性方法1和可溶性方法2的要求,如果Cmax大于可溶性限值,要进行可溶性方法1和可溶性
方法2的测试。
Sample weight, W (g) 样品重量,W(克) | Volume of concentrated nitric acid used (ml) 所用浓硝酸体积(mL) | Final makeup volume (ml) 最终定容体积 |
单独测试W ≤0.01<0.05 | 4 | 10 |
单独测试 W≤0.1±0.005 | 10 | 25 |
混合测试0.05±0.005 | 10 | 25 |